142450003433 has 8 divisors (see below), whose sum is σ = 143261167752. Its totient is φ = 141640830976.

The previous prime is 142450003429. The next prime is 142450003471. The reversal of 142450003433 is 334300054241.

142450003433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 31821921769 + 110628081664 = 178387^2 + 332608^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 142450003433 - 2² = 142450003429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142450003396 and 142450003405.

It is not an unprimeable number, because it can be changed into a prime (142450003483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 354410 + ... + 640707.

It is an arithmetic number, because the mean of its divisors is an integer number (17907645969).

Almost surely, 2^142450003433 is an apocalyptic number.

It is an amenable number.

142450003433 is a deficient number, since it is larger than the sum of its proper divisors (811164319).

142450003433 is an equidigital number, since it uses as much as digits as its factorization.

142450003433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 995931.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 142450003433 its reverse (334300054241), we get a palindrome (476750057674).

The spelling of 142450003433 in words is "one hundred forty-two billion, four hundred fifty million, three thousand, four hundred thirty-three".