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142450133112211 = 236193484048357
BaseRepresentation
bin100000011000111011000001…
…100101010001010110010011
3200200101002200200221201210211
4200120323001211101112103
5122132400333034042321
61222544404314504551
742001453044103141
oct4030730145212623
9620332620851724
10142450133112211
1141430842524671
1213b87959435157
136163cb3abb032
1427268a2200591
1511706c529d0e1
hex818ec1951593

142450133112211 has 4 divisors (see below), whose sum is σ = 148643617160592. Its totient is φ = 136256649063832.

The previous prime is 142450133112173. The next prime is 142450133112239. The reversal of 142450133112211 is 112211331054241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142450133112211 - 217 = 142450132981139 is a prime.

It is not an unprimeable number, because it can be changed into a prime (142450133112281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3096742024156 + ... + 3096742024201.

It is an arithmetic number, because the mean of its divisors is an integer number (37160904290148).

Almost surely, 2142450133112211 is an apocalyptic number.

142450133112211 is a deficient number, since it is larger than the sum of its proper divisors (6193484048381).

142450133112211 is an equidigital number, since it uses as much as digits as its factorization.

142450133112211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6193484048380.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 142450133112211 its reverse (112211331054241), we get a palindrome (254661464166452).

The spelling of 142450133112211 in words is "one hundred forty-two trillion, four hundred fifty billion, one hundred thirty-three million, one hundred twelve thousand, two hundred eleven".

Divisors: 1 23 6193484048357 142450133112211