Base | Representation |
---|---|
bin | 1000010010101010110… |
… | …1111011101011000001 |
3 | 111121200121221111110121 |
4 | 2010222231323223001 |
5 | 4313214323322422 |
6 | 145235122500241 |
7 | 13202026106350 |
oct | 2045255735301 |
9 | 447617844417 |
10 | 142450604737 |
11 | 5545a71a811 |
12 | 23736504681 |
13 | 105824b837c |
14 | 6c74ca1997 |
15 | 3a8ae418c7 |
hex | 212ab7bac1 |
142450604737 has 4 divisors (see below), whose sum is σ = 162800691136. Its totient is φ = 122100518340.
The previous prime is 142450604717. The next prime is 142450604753. The reversal of 142450604737 is 737406054241.
142450604737 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 142450604737 - 231 = 140303121089 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142450604693 and 142450604702.
It is not an unprimeable number, because it can be changed into a prime (142450604717) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10175043189 + ... + 10175043202.
It is an arithmetic number, because the mean of its divisors is an integer number (40700172784).
Almost surely, 2142450604737 is an apocalyptic number.
It is an amenable number.
142450604737 is a deficient number, since it is larger than the sum of its proper divisors (20350086399).
142450604737 is an equidigital number, since it uses as much as digits as its factorization.
142450604737 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20350086398.
The product of its (nonzero) digits is 564480, while the sum is 43.
Adding to 142450604737 its reverse (737406054241), we get a palindrome (879856658978).
The spelling of 142450604737 in words is "one hundred forty-two billion, four hundred fifty million, six hundred four thousand, seven hundred thirty-seven".
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