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142465211601 = 347488403867
BaseRepresentation
bin1000010010101110010…
…1101001110011010001
3111121201122102121022120
42010223211221303101
54313232043232401
6145240403524453
713202264214066
oct2045345516321
9447648377276
10142465211601
11554679970a9
122373b389729
1310585530a9b
146c76bc4c6d
153a8c379836
hex212b969cd1

142465211601 has 4 divisors (see below), whose sum is σ = 189953615472. Its totient is φ = 94976807732.

The previous prime is 142465211599. The next prime is 142465211621. The reversal of 142465211601 is 106112564241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142465211601 - 21 = 142465211599 is a prime.

It is not an unprimeable number, because it can be changed into a prime (142465211621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23744201931 + ... + 23744201936.

It is an arithmetic number, because the mean of its divisors is an integer number (47488403868).

Almost surely, 2142465211601 is an apocalyptic number.

It is an amenable number.

142465211601 is a deficient number, since it is larger than the sum of its proper divisors (47488403871).

142465211601 is an equidigital number, since it uses as much as digits as its factorization.

142465211601 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47488403870.

The product of its (nonzero) digits is 11520, while the sum is 33.

Adding to 142465211601 its reverse (106112564241), we get a palindrome (248577775842).

The spelling of 142465211601 in words is "one hundred forty-two billion, four hundred sixty-five million, two hundred eleven thousand, six hundred one".

Divisors: 1 3 47488403867 142465211601