Base | Representation |
---|---|
bin | 11010100010011000… |
… | …11100101011000001 |
3 | 1100202220110122212120 |
4 | 31101030130223001 |
5 | 213134230311203 |
6 | 10313421114453 |
7 | 1013025342462 |
oct | 152114345301 |
9 | 40686418776 |
10 | 14247119553 |
11 | 6051144877 |
12 | 29173b8a29 |
13 | 1460883474 |
14 | 992242d69 |
15 | 585b98b53 |
hex | 35131cac1 |
14247119553 has 4 divisors (see below), whose sum is σ = 18996159408. Its totient is φ = 9498079700.
The previous prime is 14247119527. The next prime is 14247119573. The reversal of 14247119553 is 35591174241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14247119553 - 230 = 13173377729 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14247119573) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2374519923 + ... + 2374519928.
It is an arithmetic number, because the mean of its divisors is an integer number (4749039852).
Almost surely, 214247119553 is an apocalyptic number.
It is an amenable number.
14247119553 is a deficient number, since it is larger than the sum of its proper divisors (4749039855).
14247119553 is an equidigital number, since it uses as much as digits as its factorization.
14247119553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4749039854.
The product of its digits is 151200, while the sum is 42.
The spelling of 14247119553 in words is "fourteen billion, two hundred forty-seven million, one hundred nineteen thousand, five hundred fifty-three".
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