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1425130555 = 5285026111
BaseRepresentation
bin101010011110001…
…1100010000111011
310200022122010121011
41110330130100323
510404313134210
6353225254351
750213260402
oct12474342073
93608563534
101425130555
116714a3752
123393343b7
1319933a224
14d73b4639
15851aad8a
hex54f1c43b

1425130555 has 4 divisors (see below), whose sum is σ = 1710156672. Its totient is φ = 1140104440.

The previous prime is 1425130523. The next prime is 1425130571. The reversal of 1425130555 is 5550315241.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1425130555 - 25 = 1425130523 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142513051 + ... + 142513060.

It is an arithmetic number, because the mean of its divisors is an integer number (427539168).

Almost surely, 21425130555 is an apocalyptic number.

1425130555 is a deficient number, since it is larger than the sum of its proper divisors (285026117).

1425130555 is an equidigital number, since it uses as much as digits as its factorization.

1425130555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285026116.

The product of its (nonzero) digits is 15000, while the sum is 31.

The square root of 1425130555 is about 37750.9013799671. The cubic root of 1425130555 is about 1125.3429222911.

Adding to 1425130555 its reverse (5550315241), we get a palindrome (6975445796).

The spelling of 1425130555 in words is "one billion, four hundred twenty-five million, one hundred thirty thousand, five hundred fifty-five".

Divisors: 1 5 285026111 1425130555