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14252140121 = 61923024459
BaseRepresentation
bin11010100010111111…
…00110011001011001
31100210020220201210112
431101133212121121
5213142021440441
610314120454105
71013116122632
oct152137463131
940706821715
1014252140121
116053a638aa
12291901a335
13146192070b
14992b8c889
1558633b4eb
hex3517e6659

14252140121 has 4 divisors (see below), whose sum is σ = 14275165200. Its totient is φ = 14229115044.

The previous prime is 14252140109. The next prime is 14252140127. The reversal of 14252140121 is 12104125241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14252140121 - 218 = 14251877977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14252140127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11511611 + ... + 11512848.

It is an arithmetic number, because the mean of its divisors is an integer number (3568791300).

Almost surely, 214252140121 is an apocalyptic number.

It is an amenable number.

14252140121 is a deficient number, since it is larger than the sum of its proper divisors (23025079).

14252140121 is an equidigital number, since it uses as much as digits as its factorization.

14252140121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23025078.

The product of its (nonzero) digits is 640, while the sum is 23.

Adding to 14252140121 its reverse (12104125241), we get a palindrome (26356265362).

The spelling of 14252140121 in words is "fourteen billion, two hundred fifty-two million, one hundred forty thousand, one hundred twenty-one".

Divisors: 1 619 23024459 14252140121