Search a number
-
+
142535140343555 = 528507028068711
BaseRepresentation
bin100000011010001010001100…
…011010000111111100000011
3200200200020010000001111220112
4200122022030122013330003
5122140243431411443210
61223051423422501535
742010552436460641
oct4032121432077403
9620606100044815
10142535140343555
11414638a4927773
1213ba03221348ab
13616c01041401b
14272aa47da0191
1511729ed150d05
hex81a28c687f03

142535140343555 has 4 divisors (see below), whose sum is σ = 171042168412272. Its totient is φ = 114028112274840.

The previous prime is 142535140343539. The next prime is 142535140343581. The reversal of 142535140343555 is 555343041535241.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 142535140343555 - 24 = 142535140343539 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14253514034351 + ... + 14253514034360.

It is an arithmetic number, because the mean of its divisors is an integer number (42760542103068).

Almost surely, 2142535140343555 is an apocalyptic number.

142535140343555 is a deficient number, since it is larger than the sum of its proper divisors (28507028068717).

142535140343555 is an equidigital number, since it uses as much as digits as its factorization.

142535140343555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28507028068716.

The product of its (nonzero) digits is 10800000, while the sum is 50.

Adding to 142535140343555 its reverse (555343041535241), we get a palindrome (697878181878796).

The spelling of 142535140343555 in words is "one hundred forty-two trillion, five hundred thirty-five billion, one hundred forty million, three hundred forty-three thousand, five hundred fifty-five".

Divisors: 1 5 28507028068711 142535140343555