Base | Representation |
---|---|
bin | 100000011010001010001100… |
… | …011010000111111100000011 |
3 | 200200200020010000001111220112 |
4 | 200122022030122013330003 |
5 | 122140243431411443210 |
6 | 1223051423422501535 |
7 | 42010552436460641 |
oct | 4032121432077403 |
9 | 620606100044815 |
10 | 142535140343555 |
11 | 414638a4927773 |
12 | 13ba03221348ab |
13 | 616c01041401b |
14 | 272aa47da0191 |
15 | 11729ed150d05 |
hex | 81a28c687f03 |
142535140343555 has 4 divisors (see below), whose sum is σ = 171042168412272. Its totient is φ = 114028112274840.
The previous prime is 142535140343539. The next prime is 142535140343581. The reversal of 142535140343555 is 555343041535241.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 142535140343555 - 24 = 142535140343539 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14253514034351 + ... + 14253514034360.
It is an arithmetic number, because the mean of its divisors is an integer number (42760542103068).
Almost surely, 2142535140343555 is an apocalyptic number.
142535140343555 is a deficient number, since it is larger than the sum of its proper divisors (28507028068717).
142535140343555 is an equidigital number, since it uses as much as digits as its factorization.
142535140343555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28507028068716.
The product of its (nonzero) digits is 10800000, while the sum is 50.
Adding to 142535140343555 its reverse (555343041535241), we get a palindrome (697878181878796).
The spelling of 142535140343555 in words is "one hundred forty-two trillion, five hundred thirty-five billion, one hundred forty million, three hundred forty-three thousand, five hundred fifty-five".
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