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14253544113 = 34751181371
BaseRepresentation
bin11010100011001001…
…11101001010110001
31100210100120001201020
431101210331022301
5213142401402423
610314210530053
71013134061124
oct152144751261
940710501636
1014253544113
116054832726
122919596929
131461cc2793
149930363bb
155865174e3
hex35193d2b1

14253544113 has 4 divisors (see below), whose sum is σ = 19004725488. Its totient is φ = 9502362740.

The previous prime is 14253544103. The next prime is 14253544121. The reversal of 14253544113 is 31144535241.

14253544113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14253544113 - 212 = 14253540017 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14253544103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2375590683 + ... + 2375590688.

It is an arithmetic number, because the mean of its divisors is an integer number (4751181372).

Almost surely, 214253544113 is an apocalyptic number.

It is an amenable number.

14253544113 is a deficient number, since it is larger than the sum of its proper divisors (4751181375).

14253544113 is an equidigital number, since it uses as much as digits as its factorization.

14253544113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4751181374.

The product of its digits is 28800, while the sum is 33.

The spelling of 14253544113 in words is "fourteen billion, two hundred fifty-three million, five hundred forty-four thousand, one hundred thirteen".

Divisors: 1 3 4751181371 14253544113