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142536543145 = 528507308629
BaseRepresentation
bin1000010010111111010…
…1110000101110101001
3111121220121122121210121
42010233311300232221
54313403323340040
6145251432443241
713204121424553
oct2045765605651
9447817577717
10142536543145
11554a4187597
122375b249521
13105972476b9
146c824724d3
153a93769c4a
hex212fd70ba9

142536543145 has 4 divisors (see below), whose sum is σ = 171043851780. Its totient is φ = 114029234512.

The previous prime is 142536543143. The next prime is 142536543157. The reversal of 142536543145 is 541345635241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 26669829481 + 115866713664 = 163309^2 + 340392^2 .

It is a cyclic number.

It is not a de Polignac number, because 142536543145 - 21 = 142536543143 is a prime.

It is a super-2 number, since 2×1425365431452 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (142536543143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14253654310 + ... + 14253654319.

It is an arithmetic number, because the mean of its divisors is an integer number (42760962945).

Almost surely, 2142536543145 is an apocalyptic number.

It is an amenable number.

142536543145 is a deficient number, since it is larger than the sum of its proper divisors (28507308635).

142536543145 is an equidigital number, since it uses as much as digits as its factorization.

142536543145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28507308634.

The product of its digits is 864000, while the sum is 43.

The spelling of 142536543145 in words is "one hundred forty-two billion, five hundred thirty-six million, five hundred forty-three thousand, one hundred forty-five".

Divisors: 1 5 28507308629 142536543145