Base | Representation |
---|---|
bin | 1000010011000000111… |
… | …1101001111101001001 |
3 | 111121221002102111012000 |
4 | 2010300033221331021 |
5 | 4313412043044040 |
6 | 145252234141213 |
7 | 13204233215625 |
oct | 2046017517511 |
9 | 447832374160 |
10 | 142543331145 |
11 | 554a7aa3506 |
12 | 23761581809 |
13 | 10598783277 |
14 | 6c8331c185 |
15 | 3a9415b130 |
hex | 21303e9f49 |
142543331145 has 16 divisors (see below), whose sum is σ = 253410366720. Its totient is φ = 76023109872.
The previous prime is 142543331087. The next prime is 142543331171. The reversal of 142543331145 is 541133345241.
142543331145 is a `hidden beast` number, since 1 + 42 + 543 + 3 + 31 + 1 + 45 = 666.
It is not a de Polignac number, because 142543331145 - 218 = 142543069001 is a prime.
It is a super-2 number, since 2×1425433311452 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 527938129 + ... + 527938398.
It is an arithmetic number, because the mean of its divisors is an integer number (15838147920).
Almost surely, 2142543331145 is an apocalyptic number.
142543331145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
142543331145 is a deficient number, since it is larger than the sum of its proper divisors (110867035575).
142543331145 is a wasteful number, since it uses less digits than its factorization.
142543331145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1055876541 (or 1055876535 counting only the distinct ones).
The product of its digits is 86400, while the sum is 36.
Adding to 142543331145 its reverse (541133345241), we get a palindrome (683676676386).
The spelling of 142543331145 in words is "one hundred forty-two billion, five hundred forty-three million, three hundred thirty-one thousand, one hundred forty-five".
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