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142553536603 = 612336943223
BaseRepresentation
bin1000010011000011011…
…0100101100001011011
3111121221210121222102221
42010300312211201123
54313422201132403
6145253241004511
713204416032302
oct2046066454133
9447853558387
10142553536603
1155502833a75
1223764a83737
131059a9174ba
146c84817439
153a94ec4dbd
hex2130da585b

142553536603 has 4 divisors (see below), whose sum is σ = 144890479888. Its totient is φ = 140216593320.

The previous prime is 142553536589. The next prime is 142553536621. The reversal of 142553536603 is 306635355241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142553536603 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 142553536603.

It is not an unprimeable number, because it can be changed into a prime (142553536003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1168471551 + ... + 1168471672.

It is an arithmetic number, because the mean of its divisors is an integer number (36222619972).

Almost surely, 2142553536603 is an apocalyptic number.

142553536603 is a deficient number, since it is larger than the sum of its proper divisors (2336943285).

142553536603 is an equidigital number, since it uses as much as digits as its factorization.

142553536603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2336943284.

The product of its (nonzero) digits is 972000, while the sum is 43.

The spelling of 142553536603 in words is "one hundred forty-two billion, five hundred fifty-three million, five hundred thirty-six thousand, six hundred three".

Divisors: 1 61 2336943223 142553536603