14255441131 has 4 divisors (see below), whose sum is σ = 14456222064. Its totient is φ = 14054660200.

The previous prime is 14255441119. The next prime is 14255441191. The reversal of 14255441131 is 13114455241.

14255441131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14255441131 - 2²⁹ = 13718570219 is a prime.

It is a super-2 number, since 2×14255441131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14255441093 and 14255441102.

It is not an unprimeable number, because it can be changed into a prime (14255441191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100390360 + ... + 100390501.

It is an arithmetic number, because the mean of its divisors is an integer number (3614055516).

Almost surely, 2^14255441131 is an apocalyptic number.

14255441131 is a deficient number, since it is larger than the sum of its proper divisors (200780933).

14255441131 is an equidigital number, since it uses as much as digits as its factorization.

14255441131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200780932.

The product of its digits is 9600, while the sum is 31.

Adding to 14255441131 its reverse (13114455241), we get a palindrome (27369896372).

The spelling of 14255441131 in words is "fourteen billion, two hundred fifty-five million, four hundred forty-one thousand, one hundred thirty-one".