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142605360433 = 433316403731
BaseRepresentation
bin1000010011001111110…
…0010001110100110001
3111122002102010220101001
42010303330101310301
54314023433013213
6145302331442001
713205615364214
oct2046374216461
9448072126331
10142605360433
115552a00aa88
122377a2b6301
13105a8590aa3
146c8b66777b
153a998101dd
hex2133f11d31

142605360433 has 4 divisors (see below), whose sum is σ = 145921764208. Its totient is φ = 139288956660.

The previous prime is 142605360281. The next prime is 142605360461. The reversal of 142605360433 is 334063506241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142605360433 - 221 = 142603263281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142605360392 and 142605360401.

It is not an unprimeable number, because it can be changed into a prime (142605360493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1658201823 + ... + 1658201908.

It is an arithmetic number, because the mean of its divisors is an integer number (36480441052).

Almost surely, 2142605360433 is an apocalyptic number.

It is an amenable number.

142605360433 is a deficient number, since it is larger than the sum of its proper divisors (3316403775).

142605360433 is an equidigital number, since it uses as much as digits as its factorization.

142605360433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3316403774.

The product of its (nonzero) digits is 155520, while the sum is 37.

Adding to 142605360433 its reverse (334063506241), we get a palindrome (476668866674).

The spelling of 142605360433 in words is "one hundred forty-two billion, six hundred five million, three hundred sixty thousand, four hundred thirty-three".

Divisors: 1 43 3316403731 142605360433