Base | Representation |
---|---|
bin | 11010100100000111… |
… | …00000000101010011 |
3 | 1100210220121212201000 |
4 | 31102003200011103 |
5 | 213201424121233 |
6 | 10315054313043 |
7 | 1013262121116 |
oct | 152203400523 |
9 | 40726555630 |
10 | 14261551443 |
11 | 6059301757 |
12 | 29201b8783 |
13 | 1463867349 |
14 | 99411c57d |
15 | 587099d13 |
hex | 3520e0153 |
14261551443 has 16 divisors (see below), whose sum is σ = 21382784640. Its totient is φ = 9393148872.
The previous prime is 14261551433. The next prime is 14261551463. The reversal of 14261551443 is 34415516241.
14261551443 is a `hidden beast` number, since 1 + 4 + 2 + 61 + 551 + 4 + 43 = 666.
It is not a de Polignac number, because 14261551443 - 210 = 14261550419 is a prime.
It is a super-2 number, since 2×142615514432 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14261551398 and 14261551407.
It is not an unprimeable number, because it can be changed into a prime (14261551433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3179721 + ... + 3184202.
It is an arithmetic number, because the mean of its divisors is an integer number (1336424040).
Almost surely, 214261551443 is an apocalyptic number.
14261551443 is a deficient number, since it is larger than the sum of its proper divisors (7121233197).
14261551443 is an equidigital number, since it uses as much as digits as its factorization.
14261551443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6364015 (or 6364009 counting only the distinct ones).
The product of its digits is 57600, while the sum is 36.
The spelling of 14261551443 in words is "fourteen billion, two hundred sixty-one million, five hundred fifty-one thousand, four hundred forty-three".
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