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142632433113 = 3160729585653
BaseRepresentation
bin1000010011010110001…
…1100011010111011001
3111122011022002100002220
42010311203203113121
54314102400324423
6145305140014253
713206364451262
oct2046543432731
9448138070086
10142632433113
11555433210a5
1223787391389
13105b107c521
146c910b3969
153a9bdab9e3
hex21358e35d9

142632433113 has 8 divisors (see below), whose sum is σ = 190294926528. Its totient is φ = 95029114224.

The previous prime is 142632433103. The next prime is 142632433117. The reversal of 142632433113 is 311334236241.

142632433113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 142632433113 - 25 = 142632433081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (142632433117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14788006 + ... + 14797647.

It is an arithmetic number, because the mean of its divisors is an integer number (23786865816).

Almost surely, 2142632433113 is an apocalyptic number.

It is an amenable number.

142632433113 is a deficient number, since it is larger than the sum of its proper divisors (47662493415).

142632433113 is a wasteful number, since it uses less digits than its factorization.

142632433113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29587263.

The product of its digits is 31104, while the sum is 33.

Adding to 142632433113 its reverse (311334236241), we get a palindrome (453966669354).

The spelling of 142632433113 in words is "one hundred forty-two billion, six hundred thirty-two million, four hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 1607 4821 29585653 88756959 47544144371 142632433113