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14266213145 = 52853242629
BaseRepresentation
bin11010100100101010…
…10010001100011001
31100211020101201100122
431102111102030121
5213204122310040
610315342243025
71013346545102
oct152225221431
940736351318
1014266213145
1160609a60a8
122921886475
13146480a152
149949b33a9
155876bb1b5
hex352552319

14266213145 has 4 divisors (see below), whose sum is σ = 17119455780. Its totient is φ = 11412970512.

The previous prime is 14266213141. The next prime is 14266213189. The reversal of 14266213145 is 54131266241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8421916441 + 5844296704 = 91771^2 + 76448^2 .

It is a cyclic number.

It is not a de Polignac number, because 14266213145 - 22 = 14266213141 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14266213141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1426621310 + ... + 1426621319.

It is an arithmetic number, because the mean of its divisors is an integer number (4279863945).

Almost surely, 214266213145 is an apocalyptic number.

It is an amenable number.

14266213145 is a deficient number, since it is larger than the sum of its proper divisors (2853242635).

14266213145 is an equidigital number, since it uses as much as digits as its factorization.

14266213145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2853242634.

The product of its digits is 34560, while the sum is 35.

Adding to 14266213145 its reverse (54131266241), we get a palindrome (68397479386).

The spelling of 14266213145 in words is "fourteen billion, two hundred sixty-six million, two hundred thirteen thousand, one hundred forty-five".

Divisors: 1 5 2853242629 14266213145