Base | Representation |
---|---|
bin | 10100110000101001011… |
… | …000000111101101001011 |
3 | 12001101100211111010222121 |
4 | 110300221120013231023 |
5 | 141333211033044042 |
6 | 3011214241032111 |
7 | 205033025143210 |
oct | 24605130075513 |
9 | 5041324433877 |
10 | 1426623331147 |
11 | 500033751003 |
12 | 1b05a5325637 |
13 | a46b7554861 |
14 | 4d0983dbb07 |
15 | 2719a5de367 |
hex | 14c29607b4b |
1426623331147 has 4 divisors (see below), whose sum is σ = 1630426664176. Its totient is φ = 1222819998120.
The previous prime is 1426623331127. The next prime is 1426623331151. The reversal of 1426623331147 is 7411333266241.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1426623331147 - 27 = 1426623331019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1426623331127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101901666504 + ... + 101901666517.
It is an arithmetic number, because the mean of its divisors is an integer number (407606666044).
Almost surely, 21426623331147 is an apocalyptic number.
1426623331147 is a deficient number, since it is larger than the sum of its proper divisors (203803333029).
1426623331147 is an equidigital number, since it uses as much as digits as its factorization.
1426623331147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 203803333028.
The product of its digits is 435456, while the sum is 43.
Adding to 1426623331147 its reverse (7411333266241), we get a palindrome (8837956597388).
The spelling of 1426623331147 in words is "one trillion, four hundred twenty-six billion, six hundred twenty-three million, three hundred thirty-one thousand, one hundred forty-seven".
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