Base | Representation |
---|---|
bin | 1000010011011111100… |
… | …1010001111110011001 |
3 | 111122021000221110111020 |
4 | 2010313321101332121 |
5 | 4314142422332411 |
6 | 145313101153053 |
7 | 13210352204655 |
oct | 2046771217631 |
9 | 448230843436 |
10 | 142671683481 |
11 | 5556349a518 |
12 | 2379855b789 |
13 | 105b9242ab2 |
14 | 6c963ada65 |
15 | 3aa0561606 |
hex | 2137e51f99 |
142671683481 has 4 divisors (see below), whose sum is σ = 190228911312. Its totient is φ = 95114455652.
The previous prime is 142671683431. The next prime is 142671683537. The reversal of 142671683481 is 184386176241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 142671683481 - 29 = 142671682969 is a prime.
It is a super-2 number, since 2×1426716834812 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (142671683431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23778613911 + ... + 23778613916.
It is an arithmetic number, because the mean of its divisors is an integer number (47557227828).
Almost surely, 2142671683481 is an apocalyptic number.
It is an amenable number.
142671683481 is a deficient number, since it is larger than the sum of its proper divisors (47557227831).
142671683481 is an equidigital number, since it uses as much as digits as its factorization.
142671683481 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47557227830.
The product of its digits is 1548288, while the sum is 51.
The spelling of 142671683481 in words is "one hundred forty-two billion, six hundred seventy-one million, six hundred eighty-three thousand, four hundred eighty-one".
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