Base | Representation |
---|---|
bin | 10100110001001111000… |
… | …111011110100101001011 |
3 | 12001102222221220120221021 |
4 | 110301033013132211023 |
5 | 141341010131040403 |
6 | 3011401140053311 |
7 | 205054514050141 |
oct | 24611707364513 |
9 | 5042887816837 |
10 | 1427256502603 |
11 | 5003290a60a8 |
12 | 1b0741394237 |
13 | a4788795b19 |
14 | 4d11853b591 |
15 | 271d5eb08bd |
hex | 14c4f1de94b |
1427256502603 has 4 divisors (see below), whose sum is σ = 1511212767480. Its totient is φ = 1343300237728.
The previous prime is 1427256502589. The next prime is 1427256502619. The reversal of 1427256502603 is 3062056527241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1427256502603 is a prime.
It is a super-2 number, since 2×14272565026032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1427256502603.
It is not an unprimeable number, because it can be changed into a prime (1427256502103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41978132413 + ... + 41978132446.
It is an arithmetic number, because the mean of its divisors is an integer number (377803191870).
Almost surely, 21427256502603 is an apocalyptic number.
1427256502603 is a deficient number, since it is larger than the sum of its proper divisors (83956264877).
1427256502603 is an equidigital number, since it uses as much as digits as its factorization.
1427256502603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83956264876.
The product of its (nonzero) digits is 604800, while the sum is 43.
The spelling of 1427256502603 in words is "one trillion, four hundred twenty-seven billion, two hundred fifty-six million, five hundred two thousand, six hundred three".
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