Search a number
-
+
143001132203 = 240131595513
BaseRepresentation
bin1000010100101110001…
…0000001110010101011
3111200002222212012011202
42011023202001302223
54320331242212303
6145405510314415
713221462365606
oct2051342016253
9450088765152
10143001132203
1155712458196
122386a958a0b
131063c581977
146cc804b33d
153abe43ac88
hex214b881cab

143001132203 has 4 divisors (see below), whose sum is σ = 143001967848. Its totient is φ = 143000296560.

The previous prime is 143001132193. The next prime is 143001132217. The reversal of 143001132203 is 302231100341.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 143001132203 - 228 = 142732696747 is a prime.

It is a super-2 number, since 2×1430011322032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143001132293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57626 + ... + 537887.

It is an arithmetic number, because the mean of its divisors is an integer number (35750491962).

Almost surely, 2143001132203 is an apocalyptic number.

143001132203 is a deficient number, since it is larger than the sum of its proper divisors (835645).

143001132203 is an equidigital number, since it uses as much as digits as its factorization.

143001132203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 835644.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 143001132203 its reverse (302231100341), we get a palindrome (445232232544).

The spelling of 143001132203 in words is "one hundred forty-three billion, one million, one hundred thirty-two thousand, two hundred three".

Divisors: 1 240131 595513 143001132203