Base | Representation |
---|---|
bin | 1101000000011000000110… |
… | …1001010100001111001011 |
3 | 1212122002010000221121010212 |
4 | 3100012001221110033023 |
5 | 3333243122013020133 |
6 | 50225215054231335 |
7 | 3004102222545221 |
oct | 320060151241713 |
9 | 55562100847125 |
10 | 14300121220043 |
11 | 461371369733a |
12 | 172b5617b554b |
13 | 7c9659c15b99 |
14 | 3761b5726b11 |
15 | 19bea4054148 |
hex | d0181a543cb |
14300121220043 has 4 divisors (see below), whose sum is σ = 15141304821240. Its totient is φ = 13458937618848.
The previous prime is 14300121219983. The next prime is 14300121220051. The reversal of 14300121220043 is 34002212100341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14300121220043 - 226 = 14300054111179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14300121220543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420591800573 + ... + 420591800606.
It is an arithmetic number, because the mean of its divisors is an integer number (3785326205310).
Almost surely, 214300121220043 is an apocalyptic number.
14300121220043 is a deficient number, since it is larger than the sum of its proper divisors (841183601197).
14300121220043 is an equidigital number, since it uses as much as digits as its factorization.
14300121220043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 841183601196.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14300121220043 its reverse (34002212100341), we get a palindrome (48302333320384).
The spelling of 14300121220043 in words is "fourteen trillion, three hundred billion, one hundred twenty-one million, two hundred twenty thousand, forty-three".
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