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143002121401 = 891606765409
BaseRepresentation
bin1000010100101110010…
…1110011010010111001
3111200010001201110002201
42011023211303102321
54320332020341101
6145405543430201
713221503655556
oct2051345632271
9450101643081
10143002121401
1155712a73407
122386b155361
131063c839ca9
146cc8227a2d
153abe583e01
hex214b9734b9

143002121401 has 4 divisors (see below), whose sum is σ = 144608886900. Its totient is φ = 141395355904.

The previous prime is 143002121359. The next prime is 143002121413. The reversal of 143002121401 is 104121200341.

143002121401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 104121200341 = 115390304597.

It can be written as a sum of positive squares in 2 ways, for example, as 83970130176 + 59031991225 = 289776^2 + 242965^2 .

It is a cyclic number.

It is not a de Polignac number, because 143002121401 - 29 = 143002120889 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143002121701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 803382616 + ... + 803382793.

It is an arithmetic number, because the mean of its divisors is an integer number (36152221725).

Almost surely, 2143002121401 is an apocalyptic number.

It is an amenable number.

143002121401 is a deficient number, since it is larger than the sum of its proper divisors (1606765499).

143002121401 is an equidigital number, since it uses as much as digits as its factorization.

143002121401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1606765498.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 143002121401 its reverse (104121200341), we get a palindrome (247123321742).

The spelling of 143002121401 in words is "one hundred forty-three billion, two million, one hundred twenty-one thousand, four hundred one".

Divisors: 1 89 1606765409 143002121401