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1430030113403 = 3104394606477
BaseRepresentation
bin10100110011110100011…
…011111101101001111011
312001201011020221121200012
4110303310123331221323
5141412200202112103
63012540300132135
7205213323256043
oct24636433755173
95051136847605
101430030113403
11501521799a31
121b119623704b
13a4b0b2b3748
144d2dca52723
15272e97362d8
hex14cf46fda7b

1430030113403 has 4 divisors (see below), whose sum is σ = 1430035030320. Its totient is φ = 1430025196488.

The previous prime is 1430030113397. The next prime is 1430030113417. The reversal of 1430030113403 is 3043110300341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1430030113403 - 26 = 1430030113339 is a prime.

It is a super-2 number, since 2×14300301134032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1430030113423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1992800 + ... + 2613677.

It is an arithmetic number, because the mean of its divisors is an integer number (357508757580).

Almost surely, 21430030113403 is an apocalyptic number.

1430030113403 is a deficient number, since it is larger than the sum of its proper divisors (4916917).

1430030113403 is an equidigital number, since it uses as much as digits as its factorization.

1430030113403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4916916.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1430030113403 its reverse (3043110300341), we get a palindrome (4473140413744).

The spelling of 1430030113403 in words is "one trillion, four hundred thirty billion, thirty million, one hundred thirteen thousand, four hundred three".

Divisors: 1 310439 4606477 1430030113403