Base | Representation |
---|---|
bin | 100000100000111110000011… |
… | …100011000010110001011011 |
3 | 200202022222002220211221212122 |
4 | 200200332003203002301123 |
5 | 122220430414114401021 |
6 | 1224050423110331455 |
7 | 42056431124451164 |
oct | 4040760343026133 |
9 | 622288086757778 |
10 | 143003143122011 |
11 | 41624324232017 |
12 | 14056b73359b8b |
13 | 61a41a54861c3 |
14 | 274556380476b |
15 | 117ec8eb45bab |
hex | 820f838c2c5b |
143003143122011 has 4 divisors (see below), whose sum is σ = 143003386702800. Its totient is φ = 143002899541224.
The previous prime is 143003143121989. The next prime is 143003143122013. The reversal of 143003143122011 is 110221341300341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 143003143122011 - 210 = 143003143120987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143003143122013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120907631 + ... + 122084648.
It is an arithmetic number, because the mean of its divisors is an integer number (35750846675700).
Almost surely, 2143003143122011 is an apocalyptic number.
143003143122011 is a deficient number, since it is larger than the sum of its proper divisors (243580789).
143003143122011 is an equidigital number, since it uses as much as digits as its factorization.
143003143122011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243580788.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 143003143122011 its reverse (110221341300341), we get a palindrome (253224484422352).
The spelling of 143003143122011 in words is "one hundred forty-three trillion, three billion, one hundred forty-three million, one hundred twenty-two thousand, eleven".
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