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143003400014003 = 575398324852941
BaseRepresentation
bin100000100000111110010010…
…110111000000100010110011
3200202022222202211020102102212
4200200332102313000202303
5122220431430400422003
61224050504404402335
742056440364136344
oct4040762267004263
9622288684212385
10143003400014003
1141624446242851
12140570253a63ab
1361a421676c8b9
1427455899960cb
15117eca748bdd8
hex820f92dc08b3

143003400014003 has 4 divisors (see below), whose sum is σ = 143003430620928. Its totient is φ = 143003369407080.

The previous prime is 143003400013961. The next prime is 143003400014021. The reversal of 143003400014003 is 300410004300341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143003400014003 - 222 = 143003395819699 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143003400014003.

It is not an unprimeable number, because it can be changed into a prime (143003400014603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6672488 + ... + 18180453.

It is an arithmetic number, because the mean of its divisors is an integer number (35750857655232).

Almost surely, 2143003400014003 is an apocalyptic number.

143003400014003 is a deficient number, since it is larger than the sum of its proper divisors (30606925).

143003400014003 is an equidigital number, since it uses as much as digits as its factorization.

143003400014003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30606924.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 143003400014003 its reverse (300410004300341), we get a palindrome (443413404314344).

The spelling of 143003400014003 in words is "one hundred forty-three trillion, three billion, four hundred million, fourteen thousand, three".

Divisors: 1 5753983 24852941 143003400014003