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14302055513 = 99114431943
BaseRepresentation
bin11010101000111100…
…00000110001011001
31100220201211200211202
431110132000301121
5213242311234023
610323102403545
71014263315564
oct152436006131
940821750752
1014302055513
11607a156a99
1229318905b5
13146c079455
149996634db
1558a8eb128
hex354780c59

14302055513 has 4 divisors (see below), whose sum is σ = 14316488448. Its totient is φ = 14287622580.

The previous prime is 14302055501. The next prime is 14302055533. The reversal of 14302055513 is 31555020341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14302055513 - 210 = 14302054489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14302055533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7214981 + ... + 7216962.

It is an arithmetic number, because the mean of its divisors is an integer number (3579122112).

Almost surely, 214302055513 is an apocalyptic number.

It is an amenable number.

14302055513 is a deficient number, since it is larger than the sum of its proper divisors (14432935).

14302055513 is an equidigital number, since it uses as much as digits as its factorization.

14302055513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14432934.

The product of its (nonzero) digits is 9000, while the sum is 29.

Adding to 14302055513 its reverse (31555020341), we get a palindrome (45857075854).

The spelling of 14302055513 in words is "fourteen billion, three hundred two million, fifty-five thousand, five hundred thirteen".

Divisors: 1 991 14431943 14302055513