1430216162113 has 4 divisors (see below), whose sum is σ = 1430347880880. Its totient is φ = 1430084443348.

The previous prime is 1430216162101. The next prime is 1430216162203. The reversal of 1430216162113 is 3112616120341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1430216162113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1430216162413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65843095 + ... + 65864812.

It is an arithmetic number, because the mean of its divisors is an integer number (357586970220).

Almost surely, 2^{1430216162113} is an apocalyptic number.

It is an amenable number.

1430216162113 is a deficient number, since it is larger than the sum of its proper divisors (131718767).

1430216162113 is a wasteful number, since it uses less digits than its factorization.

1430216162113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131718766.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 1430216162113 in words is "one trillion, four hundred thirty billion, two hundred sixteen million, one hundred sixty-two thousand, one hundred thirteen".