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14303120553 = 3213611167697
BaseRepresentation
bin11010101001000100…
…00100110010101001
31100220210211210210200
431110202010302221
5213243044324203
610323141302413
71014305342631
oct152442046251
940823753720
1014303120553
11607a814197
122932104a09
13146c360157
1499985d6c1
1558aa5b9a3
hex354884ca9

14303120553 has 12 divisors (see below), whose sum is σ = 20675260788. Its totient is φ = 9528399360.

The previous prime is 14303120551. The next prime is 14303120591. The reversal of 14303120553 is 35502130341.

It can be written as a sum of positive squares in 2 ways, for example, as 1714953744 + 12588166809 = 41412^2 + 112197^2 .

It is not a de Polignac number, because 14303120553 - 21 = 14303120551 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14303120551) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 571600 + ... + 596097.

It is an arithmetic number, because the mean of its divisors is an integer number (1722938399).

Almost surely, 214303120553 is an apocalyptic number.

It is an amenable number.

14303120553 is a deficient number, since it is larger than the sum of its proper divisors (6372140235).

14303120553 is a wasteful number, since it uses less digits than its factorization.

14303120553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1169064 (or 1169061 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

Adding to 14303120553 its reverse (35502130341), we get a palindrome (49805250894).

The spelling of 14303120553 in words is "fourteen billion, three hundred three million, one hundred twenty thousand, five hundred fifty-three".

Divisors: 1 3 9 1361 4083 12249 1167697 3503091 10509273 1589235617 4767706851 14303120553