143032012113 has 4 divisors (see below), whose sum is σ = 190709349488. Its totient is φ = 95354674740.

The previous prime is 143032012093. The next prime is 143032012129. The reversal of 143032012113 is 311210230341.

143032012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 143032012113 - 2¹² = 143032008017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143032012113.

It is not an unprimeable number, because it can be changed into a prime (143032012813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23838668683 + ... + 23838668688.

It is an arithmetic number, because the mean of its divisors is an integer number (47677337372).

Almost surely, 2^143032012113 is an apocalyptic number.

It is an amenable number.

143032012113 is a deficient number, since it is larger than the sum of its proper divisors (47677337375).

143032012113 is an equidigital number, since it uses as much as digits as its factorization.

143032012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47677337374.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 143032012113 its reverse (311210230341), we get a palindrome (454242242454).

The spelling of 143032012113 in words is "one hundred forty-three billion, thirty-two million, twelve thousand, one hundred thirteen".