14303431147 has 4 divisors (see below), whose sum is σ = 14305414816. Its totient is φ = 14301447480.

The previous prime is 14303431139. The next prime is 14303431157. The reversal of 14303431147 is 74113430341.

14303431147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14303431147 - 2³ = 14303431139 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14303431157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 980979 + ... + 995452.

It is an arithmetic number, because the mean of its divisors is an integer number (3576353704).

Almost surely, 2^14303431147 is an apocalyptic number.

14303431147 is a deficient number, since it is larger than the sum of its proper divisors (1983669).

14303431147 is an equidigital number, since it uses as much as digits as its factorization.

14303431147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1983668.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 14303431147 its reverse (74113430341), we get a palindrome (88416861488).

The spelling of 14303431147 in words is "fourteen billion, three hundred three million, four hundred thirty-one thousand, one hundred forty-seven".