Base | Representation |
---|---|
bin | 100000100001011011110101… |
… | …000111100110000101101011 |
3 | 200202110000121222101021211011 |
4 | 200201123311013212011223 |
5 | 122221441403001102311 |
6 | 1224113231322244351 |
7 | 42061642306465150 |
oct | 4041336507460553 |
9 | 622400558337734 |
10 | 143035113300331 |
11 | 4163693a5a419a |
12 | 140611b60566b7 |
13 | 61a71cba83895 |
14 | 2746d17784227 |
15 | 1180a116e1321 |
hex | 8216f51e616b |
143035113300331 has 4 divisors (see below), whose sum is σ = 163468700914672. Its totient is φ = 122601525685992.
The previous prime is 143035113300269. The next prime is 143035113300341. The reversal of 143035113300331 is 133003311530341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 143035113300331 - 219 = 143035112776043 is a prime.
It is a super-2 number, since 2×1430351133003312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 143035113300293 and 143035113300302.
It is not an unprimeable number, because it can be changed into a prime (143035113300341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10216793807160 + ... + 10216793807173.
It is an arithmetic number, because the mean of its divisors is an integer number (40867175228668).
Almost surely, 2143035113300331 is an apocalyptic number.
143035113300331 is a deficient number, since it is larger than the sum of its proper divisors (20433587614341).
143035113300331 is an equidigital number, since it uses as much as digits as its factorization.
143035113300331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20433587614340.
The product of its (nonzero) digits is 14580, while the sum is 31.
Adding to 143035113300331 its reverse (133003311530341), we get a palindrome (276038424830672).
The spelling of 143035113300331 in words is "one hundred forty-three trillion, thirty-five billion, one hundred thirteen million, three hundred thousand, three hundred thirty-one".
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