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14304220113 = 321412227031
BaseRepresentation
bin11010101001001100…
…10001001111010001
31100220212220200010010
431110212101033101
5213243340020423
610323221025133
71014320602431
oct152446211721
940825820103
1014304220113
1160803a5317
1229325551a9
13146c656791
14999a682c1
1558abc7693
hex3549913d1

14304220113 has 8 divisors (see below), whose sum is σ = 19081210176. Its totient is φ = 9531688400.

The previous prime is 14304220111. The next prime is 14304220187. The reversal of 14304220113 is 31102240341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14304220113 - 21 = 14304220111 is a prime.

It is a super-2 number, since 2×143042201132 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14304220113.

It is not an unprimeable number, because it can be changed into a prime (14304220111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1107093 + ... + 1119938.

It is an arithmetic number, because the mean of its divisors is an integer number (2385151272).

Almost surely, 214304220113 is an apocalyptic number.

It is an amenable number.

14304220113 is a deficient number, since it is larger than the sum of its proper divisors (4776990063).

14304220113 is a wasteful number, since it uses less digits than its factorization.

14304220113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2229175.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14304220113 its reverse (31102240341), we get a palindrome (45406460454).

The spelling of 14304220113 in words is "fourteen billion, three hundred four million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 2141 6423 2227031 6681093 4768073371 14304220113