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1430450352011 = 6007238130573
BaseRepresentation
bin10100110100001101011…
…111000010111110001011
312001202020112200221200002
4110310031133002332023
5141414030242231021
63013050111233215
7205226615242352
oct24641537027613
95052215627602
101430450352011
11501717a2846a
121b1292b1880b
13a4b7738cc45
144d33c7a4999
152732159650b
hex14d0d7c2f8b

1430450352011 has 4 divisors (see below), whose sum is σ = 1430688488592. Its totient is φ = 1430212215432.

The previous prime is 1430450352007. The next prime is 1430450352013. The reversal of 1430450352011 is 1102530540341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1430450352011 - 22 = 1430450352007 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1430450352013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119059280 + ... + 119071293.

It is an arithmetic number, because the mean of its divisors is an integer number (357672122148).

Almost surely, 21430450352011 is an apocalyptic number.

1430450352011 is a deficient number, since it is larger than the sum of its proper divisors (238136581).

1430450352011 is an equidigital number, since it uses as much as digits as its factorization.

1430450352011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 238136580.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 1430450352011 its reverse (1102530540341), we get a palindrome (2532980892352).

The spelling of 1430450352011 in words is "one trillion, four hundred thirty billion, four hundred fifty million, three hundred fifty-two thousand, eleven".

Divisors: 1 6007 238130573 1430450352011