Base | Representation |
---|---|
bin | 10100110100101010001… |
… | …110010001000101100011 |
3 | 12001210111010221020021112 |
4 | 110310222032101011203 |
5 | 141421022204231033 |
6 | 3013210013213535 |
7 | 205244561334233 |
oct | 24645216210543 |
9 | 5053433836245 |
10 | 1430932492643 |
11 | 5019450a68a5 |
12 | 1b13a84912ab |
13 | a4c23231064 |
14 | 4d38682bcc3 |
15 | 2734da82c48 |
hex | 14d2a391163 |
1430932492643 has 4 divisors (see below), whose sum is σ = 1430938259520. Its totient is φ = 1430926725768.
The previous prime is 1430932492637. The next prime is 1430932492699. The reversal of 1430932492643 is 3462942390341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1430932492643 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1430932492591 and 1430932492600.
It is not an unprimeable number, because it can be changed into a prime (1430932492603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2493683 + ... + 3013356.
It is an arithmetic number, because the mean of its divisors is an integer number (357734564880).
Almost surely, 21430932492643 is an apocalyptic number.
1430932492643 is a deficient number, since it is larger than the sum of its proper divisors (5766877).
1430932492643 is an equidigital number, since it uses as much as digits as its factorization.
1430932492643 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5766876.
The product of its (nonzero) digits is 3359232, while the sum is 50.
The spelling of 1430932492643 in words is "one trillion, four hundred thirty billion, nine hundred thirty-two million, four hundred ninety-two thousand, six hundred forty-three".
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