14310100345 has 4 divisors (see below), whose sum is σ = 17172120420. Its totient is φ = 11448080272.

The previous prime is 14310100327. The next prime is 14310100351. The reversal of 14310100345 is 54300101341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54300101341 = 105509 ⋅514649.

It can be written as a sum of positive squares in 2 ways, for example, as 9862277481 + 4447822864 = 99309^2 + 66692^2 .

It is a cyclic number.

It is not a de Polignac number, because 14310100345 - 2⁵ = 14310100313 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1431010030 + ... + 1431010039.

It is an arithmetic number, because the mean of its divisors is an integer number (4293030105).

Almost surely, 2^14310100345 is an apocalyptic number.

It is an amenable number.

14310100345 is a deficient number, since it is larger than the sum of its proper divisors (2862020075).

14310100345 is an equidigital number, since it uses as much as digits as its factorization.

14310100345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2862020074.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 14310100345 its reverse (54300101341), we get a palindrome (68610201686).

The spelling of 14310100345 in words is "fourteen billion, three hundred ten million, one hundred thousand, three hundred forty-five".