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14310147 = 310394591
BaseRepresentation
bin110110100101…
…101100000011
3222221000211110
4312211230003
512130411042
61230414403
7232430355
oct66455403
928830743
1014310147
118094475
124961403
132c70657
141c870d5
1513ca09c
hexda5b03

14310147 has 8 divisors (see below), whose sum is σ = 19102720. Its totient is φ = 9528840.

The previous prime is 14310091. The next prime is 14310151. The reversal of 14310147 is 74101341.

14310147 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14310147 - 27 = 14310019 is a prime.

It is a super-3 number, since 3×143101473 (a number of 22 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14310167) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 822 + ... + 5412.

It is an arithmetic number, because the mean of its divisors is an integer number (2387840).

Almost surely, 214310147 is an apocalyptic number.

14310147 is a deficient number, since it is larger than the sum of its proper divisors (4792573).

14310147 is a wasteful number, since it uses less digits than its factorization.

14310147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5633.

The product of its (nonzero) digits is 336, while the sum is 21.

The square root of 14310147 is about 3782.8754935895. The cubic root of 14310147 is about 242.7810013569.

Adding to 14310147 its reverse (74101341), we get a palindrome (88411488).

The spelling of 14310147 in words is "fourteen million, three hundred ten thousand, one hundred forty-seven".

Divisors: 1 3 1039 3117 4591 13773 4770049 14310147