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14310302121 = 327122394839
BaseRepresentation
bin11010101001111010…
…11110000110101001
31100221022100200001200
431110331132012221
5213301414131441
610323555234413
71014423363303
oct152475360651
940838320050
1014310302121
116083879875
1229345a8a09
1314709a5bbb
1499a7ac973
1558b4c97b6
hex354f5e1a9

14310302121 has 12 divisors (see below), whose sum is σ = 20961570240. Its totient is φ = 9405831960.

The previous prime is 14310302117. The next prime is 14310302161. The reversal of 14310302121 is 12120301341.

It is not a de Polignac number, because 14310302121 - 22 = 14310302117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14310302094 and 14310302103.

It is not an unprimeable number, because it can be changed into a prime (14310302161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11196781 + ... + 11198058.

It is an arithmetic number, because the mean of its divisors is an integer number (1746797520).

Almost surely, 214310302121 is an apocalyptic number.

It is an amenable number.

14310302121 is a deficient number, since it is larger than the sum of its proper divisors (6651268119).

14310302121 is a wasteful number, since it uses less digits than its factorization.

14310302121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22394916 (or 22394913 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 14310302121 its reverse (12120301341), we get a palindrome (26430603462).

The spelling of 14310302121 in words is "fourteen billion, three hundred ten million, three hundred two thousand, one hundred twenty-one".

Divisors: 1 3 9 71 213 639 22394839 67184517 201553551 1590033569 4770100707 14310302121