143104014123121 has 16 divisors (see below), whose sum is σ = 161966142632448. Its totient is φ = 125688011891200.

The previous prime is 143104014123113. The next prime is 143104014123137. The reversal of 143104014123121 is 121321410401341.

143104014123121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 143104014123121 - 2³ = 143104014123113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143104014123121.

It is not an unprimeable number, because it can be changed into a prime (143104014103121) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4463336665 + ... + 4463368726.

It is an arithmetic number, because the mean of its divisors is an integer number (10122883914528).

Almost surely, 2^{143104014123121} is an apocalyptic number.

It is an amenable number.

143104014123121 is a deficient number, since it is larger than the sum of its proper divisors (18862128509327).

143104014123121 is a wasteful number, since it uses less digits than its factorization.

143104014123121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8926705472.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 143104014123121 its reverse (121321410401341), we get a palindrome (264425424524462).

The spelling of 143104014123121 in words is "one hundred forty-three trillion, one hundred four billion, fourteen million, one hundred twenty-three thousand, one hundred twenty-one".