Base | Representation |
---|---|
bin | 10100110100110001111… |
… | …000011111101111000001 |
3 | 12001210211002202020121211 |
4 | 110310301320133233001 |
5 | 141421303104100301 |
6 | 3013230443450121 |
7 | 205251011552464 |
oct | 24646170375701 |
9 | 5053732666554 |
10 | 1431061003201 |
11 | 501a006a0775 |
12 | 1b1423526941 |
13 | a4c43a478cb |
14 | 4d3999212db |
15 | 27359eba051 |
hex | 14d31e1fbc1 |
1431061003201 has 4 divisors (see below), whose sum is σ = 1431314159572. Its totient is φ = 1430807846832.
The previous prime is 1431061003199. The next prime is 1431061003247. The reversal of 1431061003201 is 1023001601341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 728521996225 + 702539006976 = 853535^2 + 838176^2 .
It is a cyclic number.
It is not a de Polignac number, because 1431061003201 - 21 = 1431061003199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1431061003261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126569706 + ... + 126581011.
It is an arithmetic number, because the mean of its divisors is an integer number (357828539893).
Almost surely, 21431061003201 is an apocalyptic number.
It is an amenable number.
1431061003201 is a deficient number, since it is larger than the sum of its proper divisors (253156371).
1431061003201 is an equidigital number, since it uses as much as digits as its factorization.
1431061003201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 253156370.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1431061003201 its reverse (1023001601341), we get a palindrome (2454062604542).
The spelling of 1431061003201 in words is "one trillion, four hundred thirty-one billion, sixty-one million, three thousand, two hundred one".
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