Base | Representation |
---|---|
bin | 10001000011110… |
… | …11011111000011 |
3 | 100222021211221022 |
4 | 20201323133003 |
5 | 243114042011 |
6 | 22111220055 |
7 | 3355301351 |
oct | 1041733703 |
9 | 328254838 |
10 | 143112131 |
11 | 73868298 |
12 | 3bb1762b |
13 | 23859a46 |
14 | 150147d1 |
15 | c86d8db |
hex | 887b7c3 |
143112131 has 4 divisors (see below), whose sum is σ = 143309712. Its totient is φ = 142914552.
The previous prime is 143112121. The next prime is 143112149. The reversal of 143112131 is 131211341.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131211341 = 29 ⋅4524529.
It is a cyclic number.
It is not a de Polignac number, because 143112131 - 226 = 76003267 is a prime.
It is a super-2 number, since 2×1431121312 = 40962164078722322, which contains 22 as substring.
It is a Duffinian number.
It is a zygodrome in base 6.
It is not an unprimeable number, because it can be changed into a prime (143112121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97700 + ... + 99153.
It is an arithmetic number, because the mean of its divisors is an integer number (35827428).
Almost surely, 2143112131 is an apocalyptic number.
143112131 is a deficient number, since it is larger than the sum of its proper divisors (197581).
143112131 is an equidigital number, since it uses as much as digits as its factorization.
143112131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 197580.
The product of its digits is 72, while the sum is 17.
The square root of 143112131 is about 11962.9482570142. The cubic root of 143112131 is about 523.0688002282.
Adding to 143112131 its reverse (131211341), we get a palindrome (274323472).
The spelling of 143112131 in words is "one hundred forty-three million, one hundred twelve thousand, one hundred thirty-one".
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