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143112441 = 347704147
BaseRepresentation
bin10001000011110…
…11100011111001
3100222021212100210
420201323203321
5243114044231
622111221333
73355302303
oct1041734371
9328255323
10143112441
117386854a
123bb17849
1323859c24
1415014973
15c86da46
hex887b8f9

143112441 has 4 divisors (see below), whose sum is σ = 190816592. Its totient is φ = 95408292.

The previous prime is 143112439. The next prime is 143112491. The reversal of 143112441 is 144211341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 143112441 - 21 = 143112439 is a prime.

It is a super-3 number, since 3×1431124413 (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143112401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23852071 + ... + 23852076.

It is an arithmetic number, because the mean of its divisors is an integer number (47704148).

Almost surely, 2143112441 is an apocalyptic number.

It is an amenable number.

143112441 is a deficient number, since it is larger than the sum of its proper divisors (47704151).

143112441 is an equidigital number, since it uses as much as digits as its factorization.

143112441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47704150.

The product of its digits is 384, while the sum is 21.

The square root of 143112441 is about 11962.9612136795. The cubic root of 143112441 is about 523.0691779069.

Adding to 143112441 its reverse (144211341), we get a palindrome (287323782).

The spelling of 143112441 in words is "one hundred forty-three million, one hundred twelve thousand, four hundred forty-one".

Divisors: 1 3 47704147 143112441