143113121201 has 4 divisors (see below), whose sum is σ = 145459238004. Its totient is φ = 140767004400.

The previous prime is 143113121197. The next prime is 143113121219. The reversal of 143113121201 is 102121311341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 47151951025 + 95961170176 = 217145^2 + 309776^2 .

It is a cyclic number.

It is not a de Polignac number, because 143113121201 - 2² = 143113121197 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143113121101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1173058310 + ... + 1173058431.

It is an arithmetic number, because the mean of its divisors is an integer number (36364809501).

Almost surely, 2^143113121201 is an apocalyptic number.

It is an amenable number.

143113121201 is a deficient number, since it is larger than the sum of its proper divisors (2346116803).

143113121201 is an equidigital number, since it uses as much as digits as its factorization.

143113121201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2346116802.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 143113121201 its reverse (102121311341), we get a palindrome (245234432542).

The spelling of 143113121201 in words is "one hundred forty-three billion, one hundred thirteen million, one hundred twenty-one thousand, two hundred one".