Base | Representation |
---|---|
bin | 1000010101001000110… |
… | …1111010100110110001 |
3 | 111200101210220221000110 |
4 | 2011102031322212301 |
5 | 4321044001103101 |
6 | 145424554411533 |
7 | 13224323660601 |
oct | 2052215724661 |
9 | 450353827013 |
10 | 143113300401 |
11 | 5576a7aa885 |
12 | 238a0430ba9 |
13 | 10659895b96 |
14 | 6cd8cc8c01 |
15 | 3ac91e5cd6 |
hex | 215237a9b1 |
143113300401 has 16 divisors (see below), whose sum is σ = 192168892800. Its totient is φ = 94733758080.
The previous prime is 143113300349. The next prime is 143113300459. The reversal of 143113300401 is 104003311341.
It is not a de Polignac number, because 143113300401 - 222 = 143109106097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (143113300481) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1190221 + ... + 1304933.
It is an arithmetic number, because the mean of its divisors is an integer number (12010555800).
Almost surely, 2143113300401 is an apocalyptic number.
It is an amenable number.
143113300401 is a deficient number, since it is larger than the sum of its proper divisors (49055592399).
143113300401 is a wasteful number, since it uses less digits than its factorization.
143113300401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117656.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 143113300401 its reverse (104003311341), we get a palindrome (247116611742).
The spelling of 143113300401 in words is "one hundred forty-three billion, one hundred thirteen million, three hundred thousand, four hundred one".
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