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1431203141411 = 17205341007511
BaseRepresentation
bin10100110100111010010…
…110101101011100100011
312001211012000012121120222
4110310322112231130203
5141422101001011121
63013252522153255
7205254355656551
oct24647226553443
95054160177528
101431203141411
11501a7395326a
121b146305282b
13a4c67323264
144d3b0760bd1
15273676e50ab
hex14d3a5ad723

1431203141411 has 8 divisors (see below), whose sum is σ = 1516129733664. Its totient is φ = 1346358568320.

The previous prime is 1431203141399. The next prime is 1431203141437. The reversal of 1431203141411 is 1141413021341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1431203141411 - 234 = 1414023272227 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431203141111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20468855 + ... + 20538656.

It is an arithmetic number, because the mean of its divisors is an integer number (189516216708).

Almost surely, 21431203141411 is an apocalyptic number.

1431203141411 is a deficient number, since it is larger than the sum of its proper divisors (84926592253).

1431203141411 is a wasteful number, since it uses less digits than its factorization.

1431203141411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41009581.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 1431203141411 its reverse (1141413021341), we get a palindrome (2572616162752).

The spelling of 1431203141411 in words is "one trillion, four hundred thirty-one billion, two hundred three million, one hundred forty-one thousand, four hundred eleven".

Divisors: 1 17 2053 34901 41007511 697127687 84188420083 1431203141411