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14312120243 = 129111086073
BaseRepresentation
bin11010101010001000…
…11001111110110011
31100221102210001001112
431111010121332303
5213302400321433
610324102223535
71014445005041
oct152504317663
940842701045
1014312120243
116084900853
122935124bab
131471191605
1499ab23391
1558b738348
hex355119fb3

14312120243 has 4 divisors (see below), whose sum is σ = 14323207608. Its totient is φ = 14301032880.

The previous prime is 14312120233. The next prime is 14312120267. The reversal of 14312120243 is 34202121341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34202121341 = 67510479423.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14312120243 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14312120213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5541746 + ... + 5544327.

It is an arithmetic number, because the mean of its divisors is an integer number (3580801902).

Almost surely, 214312120243 is an apocalyptic number.

14312120243 is a deficient number, since it is larger than the sum of its proper divisors (11087365).

14312120243 is a wasteful number, since it uses less digits than its factorization.

14312120243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11087364.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14312120243 its reverse (34202121341), we get a palindrome (48514241584).

The spelling of 14312120243 in words is "fourteen billion, three hundred twelve million, one hundred twenty thousand, two hundred forty-three".

Divisors: 1 1291 11086073 14312120243