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14312143211 = 40733513907
BaseRepresentation
bin11010101010001000…
…11111100101101011
31100221102211012120012
431111010133211223
5213302402040321
610324102522135
71014445132022
oct152504374553
940842735505
1014312143211
116084917033
12293513634b
13147119bbc2
1499ab2b8b9
1558b74005b
hex35511f96b

14312143211 has 4 divisors (see below), whose sum is σ = 14315661192. Its totient is φ = 14308625232.

The previous prime is 14312143189. The next prime is 14312143247. The reversal of 14312143211 is 11234121341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14312143211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14312043211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1752881 + ... + 1761026.

It is an arithmetic number, because the mean of its divisors is an integer number (3578915298).

Almost surely, 214312143211 is an apocalyptic number.

14312143211 is a deficient number, since it is larger than the sum of its proper divisors (3517981).

14312143211 is an equidigital number, since it uses as much as digits as its factorization.

14312143211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3517980.

The product of its digits is 576, while the sum is 23.

Adding to 14312143211 its reverse (11234121341), we get a palindrome (25546264552).

The spelling of 14312143211 in words is "fourteen billion, three hundred twelve million, one hundred forty-three thousand, two hundred eleven".

Divisors: 1 4073 3513907 14312143211