Search a number
-
+
14312213001 = 33530081963
BaseRepresentation
bin11010101010001001…
…10000101000001001
31100221102221202022000
431111010300220021
5213302411304001
610324104221213
71014445542342
oct152504605011
940842852260
1014312213001
116084964509
12293516a809
1314711c48b8
1499ab490c9
1558b755a86
hex355130a09

14312213001 has 8 divisors (see below), whose sum is σ = 21203278560. Its totient is φ = 9541475316.

The previous prime is 14312212991. The next prime is 14312213077. The reversal of 14312213001 is 10031221341.

14312213001 is a `hidden beast` number, since 143 + 1 + 221 + 300 + 1 = 666.

It is not a de Polignac number, because 14312213001 - 25 = 14312212969 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14312213801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 265040955 + ... + 265041008.

It is an arithmetic number, because the mean of its divisors is an integer number (2650409820).

Almost surely, 214312213001 is an apocalyptic number.

It is an amenable number.

14312213001 is a deficient number, since it is larger than the sum of its proper divisors (6891065559).

14312213001 is an equidigital number, since it uses as much as digits as its factorization.

14312213001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 530081972 (or 530081966 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 14312213001 its reverse (10031221341), we get a palindrome (24343434342).

The spelling of 14312213001 in words is "fourteen billion, three hundred twelve million, two hundred thirteen thousand, one".

Divisors: 1 3 9 27 530081963 1590245889 4770737667 14312213001