1431300113 has 4 divisors (see below), whose sum is σ = 1431619440. Its totient is φ = 1430980788.

The previous prime is 1431300089. The next prime is 1431300121. The reversal of 1431300113 is 3110031341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3110031341 = 2393 ⋅1299637.

It is a cyclic number.

It is not a de Polignac number, because 1431300113 - 2⁶ = 1431300049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1431300091 and 1431300100.

It is not an unprimeable number, because it can be changed into a prime (1431300173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152843 + ... + 161936.

It is an arithmetic number, because the mean of its divisors is an integer number (357904860).

Almost surely, 2^1431300113 is an apocalyptic number.

It is an amenable number.

1431300113 is a deficient number, since it is larger than the sum of its proper divisors (319327).

1431300113 is an equidigital number, since it uses as much as digits as its factorization.

1431300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 319326.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1431300113 is about 37832.5271823070. The cubic root of 1431300113 is about 1126.9644985506.

Adding to 1431300113 its reverse (3110031341), we get a palindrome (4541331454).

The spelling of 1431300113 in words is "one billion, four hundred thirty-one million, three hundred thousand, one hundred thirteen".