Base | Representation |
---|---|
bin | 10100110101000000111… |
… | …011000011111011110001 |
3 | 12001211110200112222102000 |
4 | 110311000323003323301 |
5 | 141422312203142001 |
6 | 3013311500044213 |
7 | 205260164413005 |
oct | 24650073037361 |
9 | 5054420488360 |
10 | 1431313334001 |
11 | 502020076621 |
12 | 1b1493b33669 |
13 | a4c840c5185 |
14 | 4d3c1246705 |
15 | 2737220ea86 |
hex | 14d40ec3ef1 |
1431313334001 has 16 divisors (see below), whose sum is σ = 2188866270720. Its totient is φ = 923427956880.
The previous prime is 1431313333993. The next prime is 1431313334027. The reversal of 1431313334001 is 1004333131341.
1431313334001 is a `hidden beast` number, since 1 + 4 + 3 + 1 + 313 + 3 + 340 + 0 + 1 = 666.
It is not a de Polignac number, because 1431313334001 - 23 = 1431313333993 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (1431313334081) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 855025050 + ... + 855026723.
It is an arithmetic number, because the mean of its divisors is an integer number (136804141920).
Almost surely, 21431313334001 is an apocalyptic number.
It is an amenable number.
1431313334001 is a deficient number, since it is larger than the sum of its proper divisors (757552936719).
1431313334001 is a wasteful number, since it uses less digits than its factorization.
1431313334001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1710051813 (or 1710051807 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 1431313334001 its reverse (1004333131341), we get a palindrome (2435646465342).
The spelling of 1431313334001 in words is "one trillion, four hundred thirty-one billion, three hundred thirteen million, three hundred thirty-four thousand, one".
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